Mars august 14 2020 625mm QHY5III 178M C

[Luc CATHALA]

Hello
My last Mars pictures.
Clear skies.
Luc

[JayTee]

Wow, great image size and great resolution. I've gone as far as 5600mm for FL. I would need a 4X barlow to get close to your 13,650. Seeing your results, it may be worth a try.

Thanks for sharing this amazing image.

Cheers,
JT

[gcisko]

Wow, great image size and great resolution. I've gone as far as 5600mm for FL. I would need a 4X barlow to get close to your 13,650. Seeing your results, it may be worth a try.

Thanks for sharing this amazing image.

Cheers,
JT

This brings up an interesting point. At some point the magnification will be too high. For visual it is something like 50x per inch aperture I thought. Isn't this the same for imaging? I never have seen this addressed.

[gcisko]

Awesome image and great details... But where are the canals?

[Greenman]

Awesome image and great details... But where are the canals?

Agreed on the image. The canals are closed for maintenance

[Gordon]

Congratulations Luc on having your image selected as todays TSS APOD!

app.php/article/8-28-2020-tss-astrophot ... of-the-day

[Makuser]

Hi Luc. A very nice pair of Mars images from you. I enjoyed both the B&W and color versions. Thanks for posting these on here Luc, and congratulations on winning the TSS APOD Award today.

[Luc CATHALA]

Thank for your messages and TSSAPOD.
The link for the picture at 100% : https://cdn.astrobin.com/thumbs/OmfJJbv ... XURFLk.jpg
Clear skies.
Luc

[notFritzArgelander]

An exquisite image. Thanks for making and sharing it!

[Ylem]

Awesome!
Very nice
Simply Stunning

[OzEclipse]

Remarkable image Luc. Nice "little" scope you have there!

Congratulations on the APOD

Joe

[Juno16]

Beautiful!

Congratulations on the apod!

[Ruud]

Hi Luc, you show us some really good Mars images.
Congratulations on the APOD award and thanks for sharing!

[TheButcher]

Excellent! And congrats on the APOD!

[yobbo89]

dang, best amateur mars i've seen! . any chances of neptune ?

[Star Dad]

If you notice it looks like he took 1500 of 30,000 images to stack. I have a 5x barlow that would get me to 5,000mm, but I've not been able to find Mars/obtain focus. You have now inspired me to retry doing it. Very impressive!

[Peter802]

Luc.
As always fantastic images.
Thank you for sharing them with us.

[SkyHiker]

Wow, great image size and great resolution. I've gone as far as 5600mm for FL. I would need a 4X barlow to get close to your 13,650. Seeing your results, it may be worth a try.

Thanks for sharing this amazing image.

Cheers,
JT

This brings up an interesting point. At some point the magnification will be too high. For visual it is something like 50x per inch aperture I thought. Isn't this the same for imaging? I never have seen this addressed.

That's why he does this with a 25" Newt! So, 50x per inch is 1250x in this case.

This applies to AP as well, namely it's all about angular resolution. So if the Rayleigh criterion says 1.22*lambda/D where D=625, lambda=6000 Angstrom, that's 1.22*6e-7/0.625=0.0000012 radians or 0.0000671 degrees or 0.2416 arc second. It should now be about 25" so the disc resolution is about 100 times the smallest visible feature.

[gcisko]

That's why he does this with a 25" Newt! So, 50x per inch is 1250x in this case.

This applies to AP as well, namely it's all about angular resolution. So if the Rayleigh criterion says 1.22*lambda/D where D=625, lambda=6000 Angstrom, that's 1.22*6e-7/0.625=0.0000012 radians or 0.0000671 degrees or 0.2416 arc second. It should now be about 25" so the disc resolution is about 100 times the smallest visible feature.

25" mirror? What? Well that explains quite a lot!

Opps. My french is so good, I saw 625mm and never thought it was the aperture. Thanks for the awesome explanation.

[OzEclipse]

That's why he does this with a 25" Newt! So, 50x per inch is 1250x in this case.

This applies to AP as well, namely it's all about angular resolution. So if the Rayleigh criterion says 1.22*lambda/D where D=625, lambda=6000 Angstrom, that's 1.22*6e-7/0.625=0.0000012 radians or 0.0000671 degrees or 0.2416 arc second. It should now be about 25" so the disc resolution is about 100 times the smallest visible feature.

25" mirror? What? Well that explains quite a lot!

Opps. My french is so good, I saw 625mm and never thought it was the aperture. Thanks for the awesome explanation.

If you search all Luc's posts, just click on his username then on his profile page click "Search all posts by user." You'll see some remarkable lunar imaging that he has posted in the past.
Joe